Java 遍历Map时 删除元素

package net.nie.test;import java.util.HashMap;import java.util.Iterator;import java.util.Map;public class HashMapTest {   private static Map<Integer, String> map=new HashMap<Integer,String>();           public static void main(String[] args) {        map.put(1,"one");        map.put(2,"two");        map.put(3,"three");        map.put(4,"four");        map.put(5,"five");        map.put(6,"six");        map.put(7,"seven");        map.put(8,"eight");        map.put(5,"five");        map.put(9,"nine");        map.put(10,"ten");        Iterator<Map.Entry<Integer, String>> it = map.entrySet().iterator();        while(it.hasNext()){            Map.Entry<Integer, String> entry=it.next();            int key=entry.getKey();            if(key%2==1){                System.out.println("delete this: "+key+" = "+key);                //map.put(key, "奇数");   //ConcurrentModificationException                //map.remove(key);      //ConcurrentModificationException                it.remove();        //OK             }        }        //遍历当前的map；这种新的for循环无法修改map内容，因为不通过迭代器。        System.out.println("-------nt最终的map的元素遍历：");        for(Map.Entry<Integer, String> entry:map.entrySet()){            int k=entry.getKey();            String v=entry.getValue();            System.out.println(k+" = "+v);        }    }}