之前给大家分享的python 多线程抓取网页，不过这个只能用python 来抓取到网页的源代码，如果你想用做python 下载文件的话，上面的可能就不适合你了，最近我在用python 做文件下载的时候就遇到这个问题了，不过最终得以解决，我把代码发出来
Python实现批量下载文件
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 #!/usr/bin/env python # -*- coding:utf-8 -*- from gevent import monkey monkey.patch_all() from gevent.pool import Pool import requests import sys import os def download(url): chrome = 'Mozilla/5.0 (X11; Linux i86_64) AppleWebKit/537.36 ' + '(KHTML, like Gecko) Chrome/41.0.2272.101 Safari/537.36' headers = {'User-Agent': chrome} filename = url.split('/')[-1].strip() r = requests.get(url.strip(), headers=headers, stream=True) with open(filename, 'wb') as f: for chunk in r.iter_content(chunk_size=1024): if chunk: f.write(chunk) f.flush() print filename,"is ok" def removeLine(key, filename): os.system('sed -i /%s/d %s' % (key, filename)) if __name__ =="__main__": if len(sys.argv) == 2: filename = sys.argv[1] f = open(filename,"r") p = Pool(4) for line in f.readlines(): if line: p.spawn(download, line.strip()) key = line.split('/')[-1].strip() removeLine(key, filename) f.close() p.join() else: print 'Usage: python %s urls.txt' % sys.argv[0]其他网友的方法：
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 from os.path import basename from urlparse import urlsplit def url2name(url): return basename(urlsplit(url)[2]) def download(url, localFileName = None): localName = url2name(url) req = urllib2.Request(url) r = urllib2.urlopen(req) if r.info().has_key('Content-Disposition'): # If the response has Content-Disposition, we take file name from it localName = r.info()['Content-Disposition'].split('filename=')[1] if localName[0] == '"' or localName[0] == "'": localName = localName[1:-1] elif r.url != url: # if we were redirected, the real file name we take from the final URL localName = url2name(r.url) if localFileName: # we can force to save the file as specified name localName = localFileName f = open(localName, 'wb') f.write(r.read()) f.close() download(r'你要下载的python文件的url地址')以上便是本文给大家分享的全部内容了，小伙伴们可以测试下哪种方法效率更高呢。
