本文实例讲述了Python3处理文件中每个词的方法。分享给大家供大家参考。具体实现方法如下：
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 ''''' Created on Dec 21, 2012 处理文件中的每个词 @author: liury_lab ''' import codecs the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') for line in the_file: for word in line.split(): print(word, end = "|") the_file.close() # 若词的定义有变，可使用正则表达式 # 如词被定义为数字字母，连字符或单引号构成的序列 import re the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') print() print('************************************************************************') re_word = re.compile('[w'-]+') for line in the_file: for word in re_word.finditer(line): print(word.group(0), end = "|") the_file.close() # 封装成迭代器 def words_of_file(file_path, line_to_words = str.split): the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') for line in the_file: for word in line_to_words(line): yield word the_file.close() print() print('************************************************************************') for word in words_of_file('d:/text.txt'): print(word, end = '|') def words_by_re(file_path, repattern = '[w'-]+'): the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8') re_word = re.compile('[w'-]+') def line_to_words(line): for mo in re_word.finditer(line): yield mo.group(0) # 原书为return，发现结果不对，改为yield return words_of_file(file_path, line_to_words) print() print('************************************************************************') for word in words_by_re('d:/text.txt'): print(word, end = '|')希望本文所述对大家的Python程序设计有所帮助。
